# Arithmetic Operator Mock Test -1

 Question 1
What is the output of the following program?
``````#include < stdio.h >
int main()
{
int a,b;
a=1,2,3,4;
b=(1,2,3,4);
printf("%d %d",a,b);
return 0;
}
``````
 A 1 1 B 1 4 C 4 4 D Compiler Error
C Programming
Question 1 Explanation:
First evaluate a=1,2,3,4;
In this statement total 2 types of operator are there(= and ,).
Precedence of (=) operator is higher than (,).
Hence, first a=1 gets evaluated by compiler and 1 is assigned to a.
Now, a=1 statement return 1
Therefore, statement become 1,2,3,4.
(,) operator return the right side operand as answer but there is no variable to store this value.

In second statement b=(1,2,3,4)
First (1,2,3,4) evaluted due to brackets and return 4 which gets stored in b.

OUTPUT: 1 4 Click to Join Our Telegram Group for Latest Update of MOCK TEST Question 2
How many time Hello will be printed in the output of following program?
``````#include < stdio.h >
int main()
{
int i,j;
for(i=0,j=0;i<10,j<20;i++,j++)
{
printf("Hello\n");
}
return 0;
}``````
 A 200 B 10 C 20 D Compiler Error
C Programming
Question 2 Explanation:
This question is based on the concept of comma operator.

Condition of for loop i<10,j<20 is evaluted as Ex. x,y return y.
Therefore, i<10,j<20 is evaluted as true till j<20 is true.

So This program print Hello 20 times.

OUTPUT: 20 times Click to Join Our Telegram Group for Latest Update of MOCK TEST Question 3
What is the output of the following program?
``````#include < stdio.h >
int main()
{
int i;
if(i=0,2,4)
printf("Comment Yes");
else
printf("Comment No");
printf("%d",i);
return 0;
}``````
 A Comment Yes0 B Comment Yes4 C Comment No0 D Comment No4
C Programming
Question 3 Explanation:
Here condition part of if is i=0,2,4

In i=0,2,4 arithmatic expression (=) has higher priority compared to (,)
So, i=0 gets evaluted first and 0 is stored in i.
After that remaining expression becomes 0,2,4 (i=0 return 0 to original expression)
0,2,4 evaluted using (,) operator as Ex. x,y return y. So 0,2,4 evaluted as 4.
Hence, final condition part of if can be written as if(4).
Any non-zero value is considered as true in C. Hence, condition of if statement is true and as a result Comment Yes0 will be printed by program.

OUTPUT: Comment Yes0 Click to Join Our Telegram Group for Latest Update of MOCK TEST Question 4
What is the output of the following program?
``````#include < stdio.h >
int main()
{
int a=(printf("practicepaper"),3);
printf("%d",a);
return 0;
}``````
 A practicepaper13 B practicepaper0 C practicepaper3 D Compiler Error
C Programming
Question 4 Explanation:
In this program first (printf("practicepaper"),3) gets evaluted by compiler as x,y return y.
NOTE: (,) operator evaluted by compiler with x,y
first execute x then y and finally retun y.
Therefore, first printf function print "practicepaper" and then (printf("practicepaper"),3) return 3 which will be stored in a.

So final outout of program is practicepaper3.

OUTPUT: practicepaper3 Click to Join Our Telegram Group for Latest Update of MOCK TEST Question 5
What is the output of the following program?
``````#include < stdio.h >
int main()
{
int i=0,j=1,k;
k=(++i,++j);
printf("%d%d%d ",i,j,k);
k=(i++,j++);
printf("%d%d%d",i,j,k);
return 0;
}``````
 A 022 033 B 122 333 C 112 223 D 122 232
C Programming
Question 5 Explanation:

NOTE: (,) operator evaluted by compiler with x,y
first execute x then y and finally retun y.

In first expression k=(++i,++j);
i become 1, then j become 2 and finaly (++i,++j) return 2 which is stored in k. So k become 2.
Output of first printf is 122

In second expression k=(i++,j++);
i remain 1, then j remain 2 and finaly (i++,j++) return 2 which is stored in k. So k become 2. After that due to post increment on i and j, value of i become 2 and value of j become 3.
Output of second printf is 232

So final output by program is 122 232.

OUTPUT: 122 232 Click to Join Our Telegram Group for Latest Update of MOCK TEST There are 5 questions to complete.

### 3 thoughts on “Arithmetic Operator Mock Test -1”

1. thanks i got 2/7 now i know my level i got motivated to study harder.

2. 3. 