Question 1 |
Consider a Boolean function f(w,x,y,z) such that
\begin{array}{lll} f(w,0,0,z) & = & 1 \\ f(1,x,1,z) & =& x+z \\ f(w,1,y,z) & = & wz +y \end{array}
The number of literals in the minimal sum-of-products expression of f is ________
\begin{array}{lll} f(w,0,0,z) & = & 1 \\ f(1,x,1,z) & =& x+z \\ f(w,1,y,z) & = & wz +y \end{array}
The number of literals in the minimal sum-of-products expression of f is ________
4 | |
6 | |
8 | |
9 |
Question 1 Explanation:
Question 2 |
Consider the following Boolean expression.
F=(X+Y+Z)(\overline X +Y)(\overline Y +Z)
Which of the following Boolean expressions is/are equivalent to \overline F (complement of F)?
[MSQ]
F=(X+Y+Z)(\overline X +Y)(\overline Y +Z)
Which of the following Boolean expressions is/are equivalent to \overline F (complement of F)?
[MSQ]
(\overline X +\overline Y +\overline Z)(X+\overline Y)(Y+\overline Z) | |
X\overline Y + \overline Z | |
(X+\overline Z)(\overline Y +\overline Z) | |
X\overline Y +Y\overline Z + \bar X \bar Y \bar Z |
Question 2 Explanation:
Question 3 |
The following circuit compares two 2-bit binary numbers, X and Y represented by X_{1}X_{0} and Y_{1}Y_{0} respectively. (X_{0} and Y_{0} represent Least Significant Bits)

Under what conditions Z will be 1?

Under what conditions Z will be 1?
X > Y | |
X < Y | |
X=Y | |
X!=Y |
Question 3 Explanation:
Question 4 |
If ABCD is a 4-bit binary number, then what is the code generated by the following circuit?


BCD code | |
Gray code | |
8421 code | |
Excess-3 code |
Question 4 Explanation:
Question 5 |
Minimum number of NAND gates required to implement the following binary equationY=(\bar{A}+\bar{B})(C+D)
4 | |
5 | |
3 | |
6 |
Question 5 Explanation:
There are 5 questions to complete.
IN Q37 THERE IS AN ERROR IN QUESTION STATEMENT …
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Q62 OPTION (A) IS CORRECT PLS CORRECT IT ….
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question no 83 ,
option and answer is wrong
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q-2
opt (d) xyz whole bar is not correct. its x bar, y bar, z bar
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Check solution of question number 104 correct option is displayed wrong please rectify it. 👍
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Please rectify the mistake in question number 58 of Boolean algebra correct answer is X
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