C Programming

What is printed by the following ANSI C program?

#include < stdio.h >
int main(int argc, char *argv[]){ 
 char a = 'P';
 char b = 'x';
 char c = (a  &  b) + '*';
 char d = (a | b) - '-';
 char e = (a ^ b) + '+'; 
 printf("%c %c %c \n", c, d, e); 
 return 0;
}

ASCII encoding for relevant characters is given below

What is printed by the following ANSI C program?

#include < stdio.h >
int main(int argc, char *argv[])
{
 int a[3][3][3] =
 {{1, 2, 3, 4, 5, 6, 7, 8, 9},
 {10, 11, 12, 13, 14, 15, 16, 17, 18},
 {19, 20, 21, 22, 23, 24, 25, 26, 27}};
int i = 0, j = 0, k = 0; 
for( i = 0; i < 3; i++ ){

     for(k = 0; k < 3; k++ ) 
      printf("%d ", a[i][j][k]);
 printf(" \n");
}
return 0;
}

What is printed by the following ANSI C program?

#include < stdio.h >
int main(int argc, char *argv[])
{
int x = 1, z[2] = {10, 11};
int *p=NULL; p=&x;
*p=10;
p =&z[1];
*(&z[0]+1)+=3;
printf("%d, %d, %d \n",x,z[0],z[1]); return   0;
}

Consider the following ANSI C program

 #include < stdio.h >
int foo(int x, int y, int q) 
    {
        if ((x < = 0) && (y < = 0))
        return q;
        if (x < = 0)
        return foo(x, y-q, q);
        if (y < = 0)
        return foo(x-q, y, q);
        return foo(x, y-q, q) + foo(x-q, y, q);
    }
int main( )
{
    int r = foo(15, 15, 10);
    printf("%d", r);
    return 0;
}

The output of the program upon execution is ____

Consider the following ANSI C code segment:

 z=x + 3 + y-> f1 + y-> f2;
for (i = 0; i < 200; i = i + 2) 
{
    if (z > i) 
    {
        p = p + x + 3;
        q = q + y-> f1;
    } else 
    {
        p = p + y-> f2;
        q = q + x + 3;
    }
}

Assume that the variable y points to a struct (allocated on the heap) containing two fields f1 and f2, and the local variables x, y, z, p, q, and i are allotted registers. Common sub-expression elimination (CSE) optimization is applied on the code. The number of addition and the dereference operations (of the form y -> f1 or y -> f2) in the optimized code, respectively, are:

Consider the following ANSI C function:

int SomeFunction (int x, int y)
{
    if ((x==1) || (y==1)) return 1;
    if (x==y) return x;
    if (x > y) return SomeFunction(x-y, y);
    if (y > x) return SomeFunction (x, y-x);
 
} 

The value returned by SomeFunction(15, 255) is __________

Consider the following ANSI C program.

 #include < stdio.h >
int main( ) 
{
    int arr[4][5];
    int  i, j;
    for (i=0; i < 4; i++) 
  {
        for (j=0; j < 5; j++) 
        {
            arr[i][j] = 10 * i + j;
        }
    }
    printf("%d", *(arr[1]+9));
    return 0;
}

What is the output of the above program?

Consider the following ANSI C function:

 int SimpleFunction(int Y[], int n, int x)
{
int total = Y[0], loopIndex;
for (loopIndex=1; loopIndex<=n-1; loopIndex++)
    total=x*total +Y[loopIndex];
return total;
}

Let Z be an array of 10 elements with Z[i]=1, for all i such that 0\leq i \leq 9. The value returned by SimpleFunction(Z,10,2) is __________

Consider the following ANSI C program.

 #include < stdio.h >
int main()
{
    int i, j, count;
    count=0;
    i=0;
    for (j=-3; j < =3; j++)
    {
        if (( j > = 0) && (i++))
        count = count + j;
    }
    count = count +i;
    printf("%d", count);
    return 0;
}

Which one of the following options is correct?

In the following procedure

 Integer procedure P(X,Y);
Integer X,Y;
value x;
begin
      K=5;
      L=8;
      P=x+y;
end

X is called by value and Y is called by name. If the procedure were invoked by the following program fragment

 K=0;
L=0;
Z=P(K,L);

then the value of Z will be set equal to