Question 1 |

Consider a Boolean function f(w,x,y,z) such that

\begin{array}{lll} f(w,0,0,z) & = & 1 \\ f(1,x,1,z) & =& x+z \\ f(w,1,y,z) & = & wz +y \end{array}

The number of literals in the minimal sum-of-products expression of f is ________

\begin{array}{lll} f(w,0,0,z) & = & 1 \\ f(1,x,1,z) & =& x+z \\ f(w,1,y,z) & = & wz +y \end{array}

The number of literals in the minimal sum-of-products expression of f is ________

4 | |

6 | |

8 | |

9 |

Question 1 Explanation:

Question 2 |

If the numerical value of a 2-byte unsigned integer on a little endian computer is 255 more than that on a big endian computer, which of the following choices represent(s) the unsigned integer on a little endian computer?

**[MSQ]**0x6665 | |

0x0001 | |

0x4243 | |

0x0100 |

Question 2 Explanation:

Question 3 |

If x and y are two decimal digits and (0.1101)_2 = (0.8xy5)_{10}, the decimal value of x+y is ___________

3 | |

6 | |

8 | |

4 |

Question 3 Explanation:

Question 4 |

Which one of the following circuits implements the Boolean function given below?

f(x,y,z) = m_0+m_1+m_3+m_4+m_5+m_6

where m_i is the i^{th} minterm.

f(x,y,z) = m_0+m_1+m_3+m_4+m_5+m_6

where m_i is the i^{th} minterm.

A | |

B | |

C | |

D |

Question 4 Explanation:

Question 5 |

The format of the single-precision floating point representation of a real number as per the IEEE 754 standard is as follows:

\begin{array}{|c|c|c|} \hline \text{sign} & \text{exponent} & \text{mantissa} \\ \hline \end{array}

Which one of the following choices is correct with respect to the smallest normalized positive number represented using the standard?

\begin{array}{|c|c|c|} \hline \text{sign} & \text{exponent} & \text{mantissa} \\ \hline \end{array}

Which one of the following choices is correct with respect to the smallest normalized positive number represented using the standard?

exponent = 00000000 and mantissa = 0000000000000000000000000 | |

exponent = 00000000 and mantissa = 0000000000000000000000001 | |

exponent = 00000001 and mantissa = 0000000000000000000000000 | |

exponent = 00000001 and mantissa = 0000000000000000000000001 |

Question 5 Explanation:

Question 6 |

Consider the following Boolean expression.

F=(X+Y+Z)(\overline X +Y)(\overline Y +Z)

Which of the following Boolean expressions is/are equivalent to \overline F (complement of F)?

F=(X+Y+Z)(\overline X +Y)(\overline Y +Z)

Which of the following Boolean expressions is/are equivalent to \overline F (complement of F)?

**[MSQ]**(\overline X +\overline Y +\overline Z)(X+\overline Y)(Y+\overline Z) | |

X\overline Y + \overline Z | |

(X+\overline Z)(\overline Y +\overline Z) | |

X\overline Y +Y\overline Z + \bar X \bar Y \bar Z |

Question 6 Explanation:

Question 7 |

Consider a 3-bit counter, designed using T flip-flops, as shown below:

Assuming the initial state of the counter given by PQR as 000, what are the next three states?

Assuming the initial state of the counter given by PQR as 000, what are the next three states?

011,101,000 | |

001,010,111 | |

011,101,111 | |

001,010,000 |

Question 7 Explanation:

Question 8 |

Consider the following representation of a number in IEEE 754 single-precision floating point format with a bias of 127.

S:1

E:10000001

F:11110000000000000000000

Here, S,E and F denote the sign, exponent, and fraction components of the floating point representation.

The decimal value corresponding to the above representation (rounded to 2 decimal places) is ____________.

S:1

E:10000001

F:11110000000000000000000

Here, S,E and F denote the sign, exponent, and fraction components of the floating point representation.

The decimal value corresponding to the above representation (rounded to 2 decimal places) is ____________.

-7.75 | |

7.75 | |

-3.825 | |

3.825 |

Question 8 Explanation:

Question 9 |

Let the representation of a number in base 3 be 210. What is the hexadecimal representation of the number?

15 | |

21 | |

D2 | |

528 |

Question 9 Explanation:

Question 10 |

A new flipflop with inputs X and Y, has the following property

\begin{array}{|c|c|c|c|} \hline \mathbf{X} & \mathbf{Y} & \text { Current state } & \text { Next state } \\ \hline 0 & 0 & Q & 1 \\ 0 & 1 & Q & \bar{Q} \\ 1 & 1 & Q & 0 \\ 1 & 0 & Q & Q \\ \hline \end{array}

Which of the following expresses the next state in terms of X,Y, current state?

\begin{array}{|c|c|c|c|} \hline \mathbf{X} & \mathbf{Y} & \text { Current state } & \text { Next state } \\ \hline 0 & 0 & Q & 1 \\ 0 & 1 & Q & \bar{Q} \\ 1 & 1 & Q & 0 \\ 1 & 0 & Q & Q \\ \hline \end{array}

Which of the following expresses the next state in terms of X,Y, current state?

(\bar{X} \wedge \bar{Q}) \vee(\bar{Y} \wedge Q) | |

(\bar{X} \wedge {Q}) \vee(\bar{Y} \wedge \bar{Q}) | |

({X} \wedge \bar{Q}) \vee({Y} \wedge {Q}) | |

({X} \wedge \bar{Q}) \vee(\bar{Y} \wedge {Q}) |

Question 10 Explanation:

There are 10 questions to complete.

Sir, Please mention the a,b,c value of question 2.

Hi Ashutosh,

Here, value of a,b,c are not required. You can write the truth table based on above circuit. Then find the answer based on truth table. See the solution provided.

Question 5, Please update the answer from 4 minimum gate to 3 minimum gate.

Hi Ashutosh,

Thank you for your suggestion. We have updated the answer from 4 to 3.

Q13 answer will be B…

Update it

Thank You akki yadav, We have updated the answer suggested by you.

Update Question No. 46. The options should be Q1Q0 instead of Q0Q1

Update Q56 as B instead of C

Thank You Sowmya Sri,

We have updated the answer.