GATE EC 2015 SET-2

Question 1
The bilateral Laplace transform of a function f(t)=\left\{\begin{matrix} 1 & if a\leq t\leq b\\ 0&otherwise \end{matrix}\right.
is
A
\frac{a-b}{s}
B
\frac{e^{x}(a-b)}{s}
C
\frac{e^{-as}-e^{-bs}}{s}
D
\frac{e^{s(a-b)}}{s}
Signals and Systems   Laplace Transform
Question 1 Explanation: 
\begin{aligned} f(t)&=\left\{\begin{array}{ll} 1 & \text { if } a \leq t \leq b \\ 0 & \text { otherwise } \end{array}\right.\\ &=U(t-\mathrm{a})-(t+b) \\ \Rightarrow \quad F(s) &=\frac{e^{-a s}-e^{-b s}}{s} \end{aligned}
Question 2
The value of x for which all the eigen-values of the matrix given below are real is \begin{bmatrix} 10 & 5+j&4 \\ x & 20 & 2\\ 4&2 & -10 \end{bmatrix}
A
5+j
B
5-j
C
1-5j
D
1+5j
Engineering Mathematics   Linear Algebra
Question 2 Explanation: 
For a matrix containing complex number, eigen values are real if and only if
\begin{array}{l} A=A^{0}=(\bar{A})^{T} \\ A=\left[\begin{array}{ccc} 10 & 5+j & 4 \\ x & 20 & 2 \\ 4 & 2 & -10 \end{array}\right] \\ A^{\theta}=(\bar{A})^{T}=\left[\begin{array}{ccc} 10 & \bar{x} & 4 \\ 5-j & 20 & 2 \\ 4 & 2 & -10 \end{array}\right] \end{array}
By comparing these,
x=5-j
Question 3
Let f(z)=\frac{az+b}{cz+d} . If f(z_{1})=f(z_{2}) \; for \; all \; z_{1}\neq z_{2} , a= 2, b = 4 and c= 5, then d should be equal to _______.
A
9
B
10
C
11
D
12
Engineering Mathematics   Complex Analysis
Question 3 Explanation: 
\begin{aligned} f\left(z_{1}\right)&=\frac{a z_{1}+b}{c z_{1}+d} \\ f\left(z_{2}\right)&=\frac{a z_{2}+b}{c z_{2}+d} \\ \frac{a z_{1}+b}{c z_{1}+d}&=\frac{a z_{2}+b}{c z_{2}+d} \\ acz_{1}z_{2}+bcz_{2}+adz_{1}&+bd=ac z_{1} z_{2}+bcz_{1}+adz_{2}+bd\\ b c\left(z_{2}-z_{1}\right)&=a d\left(z_{2}-z_{1}\right) \\ z_{2} &\neq z_{1} \\ \Rightarrow \quad b c&=a d \\ d=\frac{b c}{a}&=\frac{4 \times 5}{2}=10 \end{aligned}
Question 4
The general solution of the differential equation \frac{dy}{dx}=\frac{1+cos2y}{1-cos2x} is
A
tan y - cot x = c ( c is a constant)
B
tan x - cot y = c ( c is a constant)
C
tan y + cot x = c ( c is a constant)
D
tan x + cot y = c ( c is a constant)
Engineering Mathematics   Differential Equations
Question 4 Explanation: 
\begin{aligned} \frac{d y}{1+\cos 2 y}&=\frac{d x}{1-\cos 2 x} \\ \frac{d y}{2 \cos ^{2} y}&=\frac{d x}{2 \sin ^{2} x} \\ \sec ^{2} y d y&=\text{cosec}^{2} x d x\\ \end{aligned}
Integrating both sides, we get
\begin{aligned} \tan y&=-\cot x+c\\ \tan y+\text{cot} x&=c \end{aligned}
Question 5
The magnitude and phase of the complex Fourier series coefficients a_{k} of a periodic signal x(t) are shown in the figure. Choose the correct statement from the four choices given. Notation: C is the set of complex numbers, R is the set of purely real numbers, and P is the set of purely imaginary numbers.

A
x(t)\in R
B
x(t)\in P
C
x(t)\in (C-R)
D
the information given is not sufficient to draw any conclusion about x(t)
Signals and Systems   Fourier Series
Question 5 Explanation: 
\begin{aligned} \left|a_{k}\right|&-\text{ even symmetry} \\ \angle a_{k}&-\text{ Odd symmetry} &(\pi \text{ can be } -\pi) \end{aligned}
\Rightarrow x(t) is real.
Question 6
The voltage (V_{c}) across the capacitor (in Volts) in the network shown is ______

.
A
40
B
120
C
100
D
80
Network Theory   Sinusoidal Steady State Analysis
Question 6 Explanation: 


\begin{aligned} (80)^{2}+\left(40-V_{c}\right)^{2} &=100^{2} \\ \left(40-V_{C}\right)^{2} &=100^{2}-80^{2}=3600 \\ \left|40-V_{C}\right| &=60 \\ V_{C} &=100 \mathrm{V} \end{aligned}
Question 7
In the circuit shown, the average value of the voltage V_{ab} (in Volts) in steady state condition is________.

A
4
B
5
C
6
D
7
Network Theory   Sinusoidal Steady State Analysis
Question 7 Explanation: 


Applying superposition:
V_{ab} = 5 V [ open circuited in steady state]


V_{ab} will be sinusoid with average value zero
\Rightarrow Average V_{ab} = 5V.
Question 8
The 2-port admittance matrix of the circuit shown is given by

A
\begin{bmatrix} 0.3 & 0.2\\ 0.2& 0.3 \end{bmatrix}
B
\begin{bmatrix} 15 & 5\\ 5& 15 \end{bmatrix}
C
\begin{bmatrix} 3.33 & 5\\ 5& 3.33 \end{bmatrix}
D
\begin{bmatrix} 0.3 & 0.4\\ 0.4& 0.3 \end{bmatrix}
Network Theory   Two Port Networks
Question 8 Explanation: 


\begin{aligned} V_{1} &=6 I_{1}+4 I_{2} \\ V_{2} &=4 I_{1}+6 I_{2} \\ [Z] &=\left[\begin{array}{cc} 6 & 4 \\ 4 & 6 \end{array}\right] \\ Y&=\frac{1}{20}\left[\begin{array}{rr} 6 & -4 \\ -4 & 6 \end{array}\right]=\left[\begin{array}{rr} 0.3 & -0.2 \\ -0.2 & 0.3 \end{array}\right] \\ &\text { Ignoring negative sign: } \\ [Y]&=\left[\begin{array}{cc} 0.3 & 0.2 \\ 0.2 & 0.3 \end{array}\right] \end{aligned}
Question 9
An n-type silicon sample is uniformly illuminated with light which generates 10^{20} electron-hole pairs per cm^{3} per second. The minority carrier lifetime in the sample is 1 \mu s. In the steady state, the hole concentration in the sample is approximately 10^{x} , where x is an integer. The value of x is ___.
A
14
B
10
C
12
D
18
Electronic Devices   Basic Semiconductor Physics
Question 9 Explanation: 
The concentration of hole-electron par in
1 \mu \mathrm{sec}=10^{20} \times 10^{-6}=10^{14} / \mathrm{cm}^{3}
So, the power of 10 is 14
x=14
Question 10
A piece of silicon is doped uniformly with phosphorous with a doping concentration of 10^{16}/cm^{3}. The expected value of mobility versus doping concentration for silicon assuming full dopant ionization is shown below. The charge of an electron is 1.6 \times 10^{-19}C. The conductivity( in S cm^{-1}) of the silicon sample at 300 K is _______.

A
1.45
B
1.92
C
3.35
D
4.22
Electronic Devices   Basic Semiconductor Physics
Question 10 Explanation: 
As per the graph, mobility of electrons at the concentration 10^{16}/cm^{3} \text{ is } 1200 cm^{2}/V-s.
\begin{aligned} \text { So, } \mu_{n} &=1200 \mathrm{cm}^{2} / \mathrm{V}-\mathrm{s} \\ \sigma_{N} &=N_{D} \mathrm{q} \mu_{n} \\ &=10^{16} \times 1.6 \times 10^{-19} \times 1200=1.92 \mathrm{Scm}^{-1} \end{aligned}
There are 10 questions to complete.
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