Question 1 |

A streamline and an equipotential line in a flow field

Are parallel to each other | |

Are perpendicular to each other | |

Intersect at an acute angle | |

Are identical |

Question 1 Explanation:

Stream line and equipotential line in a flow field are perpendicular to each other

Question 2 |

If a mass of moist air in an airtight vessel is heated to a higher temperature, then

Specific humidity of the air increases | |

Specific humidity of the air decreases | |

Relative humidity of the air increases | |

Relative humidity of the air decreases |

Question 2 Explanation:

The moist air in an airtight vessel is heated to a higher temperature. This process is treated as sensible heating. In sensible heating process, the relative humidity of the air decreases with increase in dry bulb temperature at constnat specific humidity

This process is shown on psychrometic chart in Fig.

This process is shown on psychrometic chart in Fig.

Question 3 |

In a condenser of a power plant, the steam condenses at a temperature of 60^{\circ}C. The cooling water enters at 30^{\circ}C and leaves at 45^{\circ}C. The logarithmic mean temperature difference (LMTD) of the condenser is

16.2^{\circ}C | |

21.6^{\circ}C | |

30^{\circ}C | |

37.5^{\circ}C |

Question 3 Explanation:

\begin{aligned} \therefore \quad \mathrm{LMTD} &=\frac{\Delta T_{1}-\Delta T_{2}}{\ln \left(\frac{\Delta T_{1}}{\Delta T_{2}}\right)} \\ &=\frac{30-15}{\ln (2)}=21.64^{\circ} \mathrm{C} \end{aligned}

Question 4 |

A simply supported beam PQ is loaded by a moment of 1kN-m at the mid-span of the beam as shown in the figure. The reaction forces R_{P}
and R_{Q}
at supports P and Q respectively are

1kN downward, 1kN upward | |

0.5kN upward, 0.5kN downward | |

0.5kN downward, 0.5kNupward | |

1kN upward, 1kN upward |

Question 4 Explanation:

Let us assume the direction of R_{P} and R_{Q} as ,

upward. Now,

\therefore \quad R_{P}+R_{Q}=0

\therefore Taking moment about point Q we get:

\begin{aligned} R_{P} \times 1+1 &=0 \\ R_{P} &=-1 \mathrm{kN}\\ \therefore R_{Q}&=+1 \mathrm{kN} \end{aligned}

since our assume direction of R_{p} is wrong therefore

R_{P}=1 \mathrm{kN} which act in the down was direction

and R_{Q}=1 \mathrm{kN} acting in upward direction.

Question 5 |

A double - parallelogram mechanism is shown in the figure. Note that PQ is a single link. The mobility of the mechanism is

-1 | |

0 | |

1 | |

2 |

Question 5 Explanation:

This is a special case because the link between & parallel to P and Q is redundant as its presence does not effect the mechanism. Hence the DOF is 1.

There are 5 questions to complete.