Question 1 |

For the given fluctuating fatigue load, the values of stress amplitude and stress ratio are respectively

100 MPa and 5 | |

250 MPa and 5 | |

100 MPa and 0.20 | |

250 MPa and 0.20 |

Question 1 Explanation:

\sigma_{a}=\frac{\sigma_{\max }-\sigma_{\min }}{2}=\frac{250-50}{2}=100 \mathrm{MPa}

\text{Stress ratio }=\frac{\sigma _{max}}{\sigma _{min}}=\frac{50}{250}=0.2

\text{Stress ratio }=\frac{\sigma _{max}}{\sigma _{min}}=\frac{50}{250}=0.2

Question 2 |

For the same material and the mass, which of the following configurations of flywheel will have maximum mass moment of inertia about the axis of rotation OO' passing through the center of gravity.

A | |

B | |

C | |

D |

Question 2 Explanation:

I=m r^{2}

Here for the rimmed wheel, the mass m will be most far away distribution from the axis 0-0.

\therefore \;(B) is the correct answer.

Here for the rimmed wheel, the mass m will be most far away distribution from the axis 0-0.

\therefore \;(B) is the correct answer.

Question 3 |

A gear train is made up of five spur gears as shown in the figure. Gear 2 is driver and gear 6 is driven member. N_{2},N_{3}, N_{4}, N_{5} and N_{6} represent number of teeth on gears 2, 3, 4, 5, and 6 respectively. The gear(s) which act(s) as idler(s) is/are

Only 3 | |

Only 4 | |

Only 5 | |

Both 3 and 5 |

Question 3 Explanation:

Only 5

Question 4 |

In the figure, link 2 rotates with constant angular velocity \omega _{2}. A slider link 3 moves outwards with a constant relative velocity V _{Q/P}, where Q is a point on slider 3 and P is a point on link 2. The magnitude and direction of Coriolis component of acceleration is given by

2w_{2} V_{Q/P} ; direction of V_{Q/P} rotated by 90^{\circ}
in the direction of w_{2} | |

w_{2} V_{Q/P} ; direction of V_{Q/P} rotated by 90^{\circ}
in the direction of w_{2} | |

2w_{2} V_{Q/P} ; direction of V_{Q/P} rotated by 90^{\circ}
opposite to the direction of w_{2} | |

w_{2} V_{Q/P} ; direction of V_{Q/P} rotated by 90^{\circ}
opposite to the direction of w_{2} |

Question 4 Explanation:

Direction is obtained by rotating velocity vector through 90.

Question 5 |

The strain hardening exponent n of stainless steel SS 304 with distinct yield and UTS values undergoing plastic deformation is

n \lt
0 | |

n = 0 | |

0 \lt
n \lt
1 | |

n = 1 |

Question 5 Explanation:

The value of strain hardening constant (n) lies between 0 and 1

n = 0 means material is perfectly plastic solid

n = 1 means material is perfectly elastic solid

n = 0 means material is perfectly plastic solid

n = 1 means material is perfectly elastic solid

There are 5 questions to complete.