Question 1 |

Consider an n x n matrix A and a non-zero n x 1 vector p. Their product Ap=\alpha ^2p, where \alpha \in \mathbb{R} and \alpha \notin \{-1,0,1\}. Based on the given information, the eigen value of A^2 is:

\alpha | |

\alpha ^2 | |

\sqrt{\alpha } | |

\alpha ^4 |

Question 1 Explanation:

Given, A P=\alpha^{2} P

By comparison with A X=\lambda X \Rightarrow

\Rightarrow \quad \lambda=\alpha^{2}

Hence, eigen value of A is \alpha^{2}, so eigen value of A^{2} is \alpha^{4}.

By comparison with A X=\lambda X \Rightarrow

\Rightarrow \quad \lambda=\alpha^{2}

Hence, eigen value of A is \alpha^{2}, so eigen value of A^{2} is \alpha^{4}.

Question 2 |

If the Laplace transform of a function f(t)
is given by \frac{s+3}{(s+1)(s+2)} , then f(0) is

0 | |

\frac{1}{2} | |

1 | |

\frac{3}{2} |

Question 2 Explanation:

By using partial fraction concept.

\begin{aligned} f(t) &=L^{-1}\left[\frac{s+3}{(s+1)(s+2)}\right] \\ &=L^{-1}\left[\frac{2}{s+1}-\frac{1}{s+2}\right] \\ \Rightarrow \qquad f(t) &=2 e^{-t}-e^{-2 t} \\ \text { So, } \qquad f(c)&=2 e^{0}-e^{0}=2-1=1 \end{aligned}

\begin{aligned} f(t) &=L^{-1}\left[\frac{s+3}{(s+1)(s+2)}\right] \\ &=L^{-1}\left[\frac{2}{s+1}-\frac{1}{s+2}\right] \\ \Rightarrow \qquad f(t) &=2 e^{-t}-e^{-2 t} \\ \text { So, } \qquad f(c)&=2 e^{0}-e^{0}=2-1=1 \end{aligned}

Question 3 |

The mean and variance, respectively, of a binomial distribution for n
independent trials with the probability of success as p, are

\sqrt{np},np(1-2p) | |

\sqrt{np}, \sqrt{np(1-p)} | |

np,np | |

np,np(1-p) |

Question 3 Explanation:

Mean= np

Variance = npq = np(1 - p)

Variance = npq = np(1 - p)

Question 4 |

The Cast Iron which possesses all the carbon in the combined form as cementite is known as

Grey Cast Iron | |

Spheroidal Cast Iron | |

Malleable Cast Iron | |

White Cast Iron |

Question 4 Explanation:

On the basis of nature of carbon present in cast iron, it may be divided into white cast iron and gray cast iron.

In the gray cast iron, carbon is present in free form as graphite. Under very slow rate of cooling during solidification, carbon atoms get sufficient time to separate out in pure form as graphite. In addition, certain elements promote decomposition of cementite. Silicon and nickel are two commonly used graphitizing elements.

In white cast iron, carbon is present in the form of combined form as cementite. In normal conditions, carbon has a tendency to combine with iron to form cementite.

In the gray cast iron, carbon is present in free form as graphite. Under very slow rate of cooling during solidification, carbon atoms get sufficient time to separate out in pure form as graphite. In addition, certain elements promote decomposition of cementite. Silicon and nickel are two commonly used graphitizing elements.

In white cast iron, carbon is present in the form of combined form as cementite. In normal conditions, carbon has a tendency to combine with iron to form cementite.

Question 5 |

The size distribution of the powder particles used in Powder Metallurgy process can be determined by

Laser scattering | |

Laser reflection | |

Laser absorption | |

Laser penetration |

Question 5 Explanation:

Particle Size, Shape, and Distribution:

Particle size is generally controlled by screening, that is, by passing the metal powder through screens (sieves) of various mesh sizes. Several other methods also are available for particle-size analysis:

1. Sedimentation, which involves measuring the rate at which particles settle in a fluid.

2. Microscopic analysis, which may include the use of transmission and scanning- electron microscopy.

3. Light scattering from a laser that illuminates a sample, consisting of particles suspended in a liquid medium; the particles cause the light to be scattered, and a detector then digitizes the signals and computes the particle-size distribution.

4. Optical methods, such as particles blocking a beam of light, in which the particle is sensed by a photocell.

5. Suspending particles in a liquid and detecting particle size and distribution by electrical sensors.

Particle size is generally controlled by screening, that is, by passing the metal powder through screens (sieves) of various mesh sizes. Several other methods also are available for particle-size analysis:

1. Sedimentation, which involves measuring the rate at which particles settle in a fluid.

2. Microscopic analysis, which may include the use of transmission and scanning- electron microscopy.

3. Light scattering from a laser that illuminates a sample, consisting of particles suspended in a liquid medium; the particles cause the light to be scattered, and a detector then digitizes the signals and computes the particle-size distribution.

4. Optical methods, such as particles blocking a beam of light, in which the particle is sensed by a photocell.

5. Suspending particles in a liquid and detecting particle size and distribution by electrical sensors.

Question 6 |

In a CNC machine tool, the function of an interpolator is to generate

signal for the lubrication pump during machining | |

error signal for tool radius compensation during machining | |

NC code from the part drawing during post processing | |

reference signal prescribing the shape of the part to be machined |

Question 6 Explanation:

In contouring systems the machining path is usually constructed from a combination of linear and circular segments. It is only necessary to specify the coordinates of the initial and final points of each segment, and the feed rate. The operation of producing the required shape based on this information is termed interpolation and the corresponding unit is the "interpolator". The interpolator coordinates the motion along the machine axes, which are separately driven, by providing reference positions instant by instant for the position-and velocity control loops, to generate the required machining path. Typical interpolators are capable of generating linear and circular paths.

Question 7 |

The machining process that involves ablation is

Abrasive Jet Machining | |

Chemical Machining | |

Electrochemical Machining | |

Laser Beam Machining |

Question 7 Explanation:

Laser beam machining (LBM) is a nonconventional machining process, which broadly refers to the process of material removal, accomplished through the interactions between the laser and target materials. The processes can include laser drilling, cutting, grooving, writing, scribing, ablation, welding, cladding, milling, and so on. LBM is a thermal process, and unlike conventional mechanical processes, LBM removes material without mechanical engagement. In general, the workpiece is heated to melting or boiling point and removed by melt ejection, vaporization, or ablation.

Question 8 |

A PERT network has 9 activities on its critical path. The standard deviation of each activity on the critical path is 3. The standard deviation of the critical path is

3 | |

9 | |

27 | |

81 |

Question 8 Explanation:

In CPM,

\begin{array}{l} \sigma=\sqrt{\text { sum of variance along critical path }} \\ \sigma=\sqrt{\sigma^{2}+\sigma^{2}+\ldots .+\sigma^{2}} \\ \sigma=\sqrt{9 \sigma^{2}}=\sqrt{9 \times 9}=9 \end{array}

\begin{array}{l} \sigma=\sqrt{\text { sum of variance along critical path }} \\ \sigma=\sqrt{\sigma^{2}+\sigma^{2}+\ldots .+\sigma^{2}} \\ \sigma=\sqrt{9 \sigma^{2}}=\sqrt{9 \times 9}=9 \end{array}

Question 9 |

The allowance provided in between a hole and a shaft is calculated from the difference between

lower limit of the shaft and the upper limit of the hole | |

upper limit of the shaft and the upper limit of the hole | |

upper limit of the shaft and the lower limit of the hole | |

lower limit of the shaft and the lower limit of the hole |

Question 9 Explanation:

It is minimum clearance or maximum interference. It is the intentional difference between the basic dimensions of the mating parts. The allowance may be positive or negative.

Question 10 |

In forced convective heat transfer, Stanton number (St), Nusselt number (Nu), Reynolds number (Re) and Prandtl number (Pr) are related as

\text{St}=\frac{\text{Nu}}{\text{Re Pr}} | |

\text{St}=\frac{\text{Nu Pr}}{\text{Re}} | |

\text{St}=\text{Nu Pr Re} | |

\text{St}=\frac{\text{Nu Re}}{\text{Pr}} |

Question 10 Explanation:

S t=\frac{N u}{R e \times P r}

There are 10 questions to complete.